a. all the 8 people are equally eligible?
b. the committee must consist of two women and one man?In how many ways can acommittee of 3 be chosen from 4 married couples if?
a) order doesn't matter, so:
(8)C(3) 8 choose 3 = 56
b) depending on what state you're in -- we'll assume it's one where there this group will be 4 men and 4 women ...
(4)C(2) times (4)C(1)
6 (4)
24In how many ways can acommittee of 3 be chosen from 4 married couples if?
The answer is 24.
it doesn't matter what order they are chosen. There are 4 women to choose from and 4 men. There are 6 combinations for the two women. Woman 1 with any of 2,3,or 4; Woman 2 with either 3 or 4; and woman 3 with woman 4. Now, for each of these combinations, there are four possible men that could be a part of the group. So the answer then is 6 * 4 = 24.
Subscribe to:
Post Comments
(Atom)
No comments:
Post a Comment